\( ^{235} _{92}U + ^1 _0n → ^{144} _{56}Ba + ^{90} _{36}Kr +2X \) In…

Physics JAMB 2005

\( ^{235} _{92}U + ^1 _0n → ^{144} _{56}Ba + ^{90} _{36}Kr +2X \)

In the reaction above, X is

  • electron
  • proton
  • neutrino
  • neutron checkmark

The correct answer is: D

Explanation

235U + 1n → 144Ba + 90Kr + 2x9205636
In the reaction above, balancing the left with the right, show that X is neutron
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