If the radius of the earth is 6.4 x 10\(^6\)m, the escape velocity of a satellite from the earth is?
[g = 10 ms-2]
-
1.13 x 104 ms-1
- 9.00 x 103 ms-1
- 8.00 x 103 ms-1
- 1.27 x 104 ms-1
The correct answer is: A
Explanation
V = √2GM/R.
=√[2 x 6.67 x 10\(^{-11}\) x 6.0 x 10\(^24\)] / 6.4 x 10\(^6\)
= √12.506 x 10\(^7\)
= 11,183.13
OR
V =√2gR
V=√[2 * 10 * 6.4 x 10\(^6\)]
V = √128,000,000
11,313.708