The wavelength of the first overtone of a note in a closed pipe of length 33 cm is?
- 33 cm
-
44 cm
- 22 cm
- 17 cm
The correct answer is: B
Explanation
In a closed tube, the fundamental note occurs when the length of the tube l = (λ)/4,the first over tone occurs when the length of the tube l = (3)/4λ.
λ = (4)/3 l = (4)/3 x (33)/T = 44 cm