A reservoir 500 m deep is filled with a fluid of density 850 kgm-3. If the atmospheric pressure is 1.05 x 105 Nm-2, the pressure at the bottom of the reservoir is.
[g = 10ms-2]
- 4.72 x 106 Nm-2
-
4.36 x 106 Nm-2
- 4.28 x 106 Nm-2
- 4.25 x 106 Nm-2
The correct answer is: B
Explanation
In general, pressure varies with depth in the relation p = \(\rho\)gh
= 850 x 10 x 500
= 4250000
= 4.25 x 10\(^6\) Nm\(^{-2}\)
Therefore, Total pressure = 1.05 x 10\(^5\) + 4.25 x 10\(^6\) = 4.36 x 10\(^6\) Nm\(^{-2}\)