A piece of iron weights 250 N in air and 200 N in a liquid of density 1000 kgm-3. the volume of the iron is?
-
5.0 x 10-3 m-3
- 4.5 x 10-3 m-3
- 2.5 x 10-3 m-3
- 2.0 x 10-3 m-3
The correct answer is: A
Explanation
Wt in the air = 250N
wt. in the liquid = 200N
loss in wt. in the liquid = 250 - 200 = 50N
∴ mass of liquid displaced = 50N → 5kg
∴If the density of the liquid is 1000kgm-3
then the volume of the liquid = (M)/D = V = (5kg)/1000 = 0.005 → 5.0 X \(10^{-3}\)\(m^3\)