If a body mass 5kg is thrown vertically upwards with velocity u,at what height will the potential energy equal to the kinetic energy?
- h =(u)2/g
-
h = (u)2/4g
- h = (2u)2/g
- h = (u)2/2g
The correct answer is: B
Explanation
From V2 = U2 + 2as
O = U 2 - 2gH, since at maximum height H, the final velocity, v = O.
when K.E = P.E
∴ H = (U)2/2g
Halfway is the height / 2
PE = KE at (1)/2 H = (U)2 /2g x (1/2) = U2 / 4g
There is an explanation video available .