If electron are accelerated from rest through a potential difference of 10kv, what is the wavelength of the associated electron?
[m = 9.1 x 10\(^{-31}\)kg, e = 1.6 x 10\(^{-19}\)C, h = 6.6 x 10\(^{-34}\)js]
-
1.22 x 10-11m
- 3.87 x 10-10m
- 2.27 x 1011m
- 2.27 x 1014m
The correct answer is: A
Explanation
\(\lambda\) = \(\frac{h}{\sqrt{2evm}}\
= \(\frac{6.6 \times 10^{34}}{\sqrt{ 2 \times 1.6 \times 10^{-19} \times 10000 \times 9.1 \times 10^{-31}}\)
1.223 x 10\(^{-11}\)m
There is an explanation video available .