If a cage containing a truck of coal weighing 750 kg is raised to a height of 90 m in a minute, what is the total power expended?
[g = 10 ms2]
- 11.50 kw
- 12.60 kw
-
11.25 kw
- 12.10 kw
The correct answer is: C
Explanation
Power = \(\frac{work done}{time taken}\)
where 1 min = 60s
= \(\frac{mgh}{t}\)
= \(\frac{750 \times 10 \times 90}{60}\)
= 11250w or 11.25kw
There is an explanation video available .