An object of mass 80 kg is pulled on a horizontal rough ground by a force of 500 N. Find the coefficient of static friction.
[g = 10 ms-2]
- 0.8
- 0.4
- 1.0
-
0.6
The correct answer is: D
Explanation
coefficient of friction
= \(\frac{F}{R}\)
=\(\frac{F}{mg}\)
= \(\frac{500}{80 \times 10}\)
= 0.625
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