If a heavy barrel is rolled up a plane inclined at 30° to the horizontal. its velocity ratio will be?
- 3.0
- 3.1
- 3.2
-
2.0
The correct answer is: D
Explanation
V.R = \(\frac{1}{sinθ}\)
= \(\frac{1}{sin 30°}\)
= \(\frac{1}{0.5}\)
= 2
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