A heating coil rated 1000 W is used to boil off completely 2 kg of boiling water. The time required to boil the water is?
[Special latent heat of Vaporization of water = 2.3 x 10\(^6\) Jkg-1]
- 1.15 x 104s
- 1.15 x 103s
- 4.6 x 104s
-
4.6 x 103s
The correct answer is: D
Explanation
Heat supplied = Heat gained
pt = ml
T = \(\frac{ml}{p}\)
= \(\frac{2 \times 2.3 \times 10^6}{1000}\)
= 4.6 x 10\(^3\) sec
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