The pressure of two moles of an ideal gas at a temperature of 27oC and volume 10-2m3 is?
[R = 8.313 J mol-1K-1]
-
4.99 x 105 Nm-2
- 9.80 x 103 Nm-2
- 4.98 x 103 Nm-2
- 9.80 x 105 Nm-2
The correct answer is: A
Explanation
PV = nRT
| ∴ P = | nRT | = | 2 x 8.313 x 300 |
| _V | ___10-2 |
= 4.987 x 105 Nm-2
There is an explanation video available .