The radioisotope \( ^{235}_{92}U \) decays by emitting two alpha particles, three beta particles and a gamma ray. What is the mass and atomic number of the resulting element?
- 215 and 88
- 91 and 227
-
227 and 91
- 92 and 238
The correct answer is: C
Explanation
- Alpha radiation consists of helium- He\(^{4}_{2}\)
2 Alpha decay --> 2 X He\(^{4}_{2}\) = Element\(^{8}_{4}\)
- Beta particles are high energy electrons- e\(^{0}_{-1}\)
3 Beta particles --> 3 X e\(^{0}_{-1}\) = Element\(^{0}_{-3}\)
- Gamma rays are waves of electromagnetic energy, or photons.
the mass and atomic number of the resulting element = U\(^{235}_{92}\) - Elements( \(^{8}_{4}\) + \(^{0}_{-3}\) )
--> Element\(^{227}_{91}\)
There is an explanation video available .