Two balls X and Y weighing 5 g and 50 kg respectively were thrown up vertically at the same time with a velocity of 100 ms1 .How will their positions be one second later?
- X and Y will be 500 m from each other
- Y will be 500 m ahead of X
- X will be 500 m ahead of Y
-
X and Y both be 500 m from the point of throw
The correct answer is: D
Explanation
v2 = U2 - 2G s
0 = 1002 - 2 x 10 x s = 10000 - 20s
s = (10000)/20 = 500m
Which is independent of mass.the two bodies where acted upon by the same retarding force of gravity which is independent of mass of the body; therefore both will be 500 m from the point of throw.
There is an explanation video available .