A metal of volume 40 cm3 is heated from 30 °c to 90 °c, the increase in volume is
- 0.12 cm3
- 4.00 cm3
- 1.20 cm3
- 0.40 cm3
-
no correct option
The correct answer is: E
Explanation
increase in volume, DV = RV1 ∆ θ = 3α Vsub>1 Dθ= 3 x 2.0 X 10-5 x 40 x (90 - 30)
= 6 x 10-5 x 40 x 60
0.144 cm3
∴ No correct option
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