A length of wire has a frequency of 225Hz when stretched by a force of 225N. If the force increased to 324N, what is the new frequency of vibration?
-
270 Hz
- 512 Hz
- 488 Hz
- 356 Hz
The correct answer is: A
Explanation
f1 = 225Hz, T1 = 225N
f2 = ? T2 = 324N
But f ∝ √T => f = K√T
=> K = f/√T
∴ f1/√T1 = f2/√T2
225/√225 = f2/√324
| f2 = | 225√324 |
| √225 |
f2 = 270Hz
There is an explanation video available .