If a load of 1 kg stretches a cord by 1.2cm, what is the force constant of the cord? {g=10ms-2}
- 866Nm-1
-
833Nm-1
- 769Nm-1
- 667Nm-1
The correct answer is: B
Explanation
K = \(\frac{F}{e}\)K = \(\frac{1 \times 10}{\frac{0.2}{100}}\)
K = \(\frac{10}{12} \times \frac{1000}{1}\)
There is an explanation video available .