Two metals P and Q are heated through the same temperature difference. If the ratio of the linear expansivities of P to Q is 2:3 and the ratio of their
length is 3: 4 respectively, the ratio of the increase in lengths of P to Q is
-
1:2
- 2:1
- 8:9
- 9:8
The correct answer is: A
Explanation
P: \(\frac{\alpha h \theta}{\alpha h \theta}\)\(\frac{2 \times 3 \times \theta}{3 \times 4 \times \theta}\)
\(\frac{1}{2}\)
There is an explanation video available .