A simple pendulum of length 0.4m has a period of 2s. What is the period a similar pendulum of length 0.8m at the same place?
- 8s
- 4s
-
2\(\sqrt{2}s\)
- \(\sqrt{2}s\)
The correct answer is: C
Explanation
T2 = \(\sqrt{\frac{L^2 \times T_1^2}{L_1}}\)= \(\sqrt{\frac{0.8 \times 2^2}{0.4}}\)
= 2\(\sqrt{2}s\)
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