Calculate the work done when a force of 20N stretches a spring by 50mm.
-
0.5J
- 1.5J
- 2.0J
- 2.5J
The correct answer is: A
Explanation
W = \(\frac{1}{2}Fe\)W = \(\frac{1}{2}\times 20 \times 0.05\)
W = 0.5J
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