A gas at a pressure of 105Nm-2expands from 0.6m-3 to 1.2m3 at constant temperature, the work done is
- 7.0 x 106J
- 6.0 x 10 6J
- 6.0 x 10 5J
-
6.0 x 10 4J
The correct answer is: D
Explanation
W = \(\frac{W_1 \times V_1}{V_2}\)W = \(\frac{10 \times 0.6}{1.2}\)
W = 6.0 x 10 4J
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