Two liquids X and Y having the same mass are supplied with the same quantity of heat. If the temperature rise in X is twice that of Y, the ratio of specific heat capacity of X to that of Y is
- 2:1
-
1:2
- 4:1
- 1:4
The correct answer is: B
Explanation
MC\(x_\theta\) = MC\(y_\theta\)
\(x_\theta\) = 2 \(\times y_\theta\)
MC(2\(y_\theta\)) = MC\(y_\theta\)
⇒ 2C = C
=1 : 2
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