A cell of emf 1.5V is connected in series with a 1Ω resistor and a current of 0.3A flows through the resistor. Find the internal resistance of the cell
-
4.0Ω
- 3.0Ω
- 1.5Ω
- 1.0Ω
The correct answer is: A
Explanation
r = \(\frac{E}{I} - R\)r = \(\frac{1.5}{0.3} - 1\)
r = 4\(\Omega\)
There is an explanation video available .