If a current of 2.5A flows through an electrolyte for 3 hours and 1.8g of a substance is deposited, what is the mass of the substance that will be deposited if a current of 4A flows through it for 4.8 hours?
- 2.4g
- 3.2g
-
4.6g
- 4.8g
The correct answer is: C
Explanation
First let's find zz = \(\frac{M}{It}\)
z = \(\frac{1.8}{2.5 \times (3 \times 60 \times 60)}\)
Therefore, the new M equals
M = zIt
M = \(\frac{1.8 \times 4 \times 4.8 \times 60 \times 60}{2.5 \times 3 \times 60 \times 60}\)
M = 4.6g
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