When a man moves toward a plane mirror at a speed of 6m/s, the distance the man and his image increased at a speed of?
The correct answer is: C
Explanation
d = y, s = 6 m/s (The Man & Plane Mirror)d โ ฮดy, s = (5 &ndash ;6) m/s (The Man and Image)
d2 รท s1 = d2 รท s2, y รท 6 = 2y รท s + 6
Y (s + 6) = 2y ร 6
s + 6 = 12
So = 12 โ 6 = 6
Since S + 6 = 0
Then, S = 6 (substitute the value of S i.e S = 6)
Into S + 6 = 0
โดSo = S + 6 = 6 + 6 = 12 m/s
โด S = 12 m/s
There is an explanation video available .