A satellite moves in a circular orbit of radius 4R round the earth. The acceleration of the satellite in terms of g is
-
\(\frac{g}{16}\)
- \(\frac{g}{4}\)
- \(\frac{4}{g}\)
- \(\frac{16}{g}\)
The correct answer is: A
Explanation
\(\frac{g}{R^2}\) = \(\frac{g}{4^2}\) = \(\frac{g}{16}\)There is an explanation video available .