Calculate the temperature of 6 moles of an ideal gas at a pressure of 7.6 x 106Nm-2 with a volume of 10-3m3.
[R = 8.3jmol-1K-1]
- 201oC
- 126oC
-
153oC
- 185oC
The correct answer is: C
Explanation
T = \(\frac{PV}{nR}\) = \(\frac{7.6 x 10^6 x 10^-3}{6 x 8.3}\)= 153oC
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