Calculate the specific latent heat of vaporization of steam of 1.13 x 106J of heat energy is required to convert 15kg of steam to water.
- 7.53 x 105 Jkg\(^{-1}\)
- 7.53 x 10-2Jkg\(^{-1}\)
-
\(7.53 \times 10^{4}\)Jkg\(^{-1}\)
- 7.53 x 10-3Jkg\(^{-1}\)
The correct answer is: C
Explanation
Quantity of heat = mass(m) Γ specific latent heat (L)
Q = mL
L = \(\frac{Q}{m}\)
= \(\frac{1.13 \times 10^{6}}{15}\)
= \(7.53 \times 10^{4}\)Jkg\(^{-1}\)
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