From the diagram above, calculate the energy stored in the capacitor
- 4.0 x 10\(^{-2}\)J
-
4.0 x 10\(^{-4}\)J
- 8.0 x 10\(^{-4}\)J
- 8.0 x 10\(^{-2}\)J
The correct answer is: B
Explanation
c = 8µF, v = 10vEnergy stored = \(\frac{1}{2}\) cv2
= \(\frac{1}{2}\) × (8 × 10− 6) × 102
= 4 × 10\(^{-4}\)
There is an explanation video available .