The efficiency of energy conversion on the energy flow through a hydroelectric power is?
- \(\frac{E1}{E2}\)
-
\(\frac{E3}{E2}\)
- \(\frac{E2}{E1}\)+ E2
- \(\frac{E2}{E3}\) + E1
The correct answer is: B
Explanation
Efficiency = \(\frac{\text{useful energy output from machine}}{\text{energy input into machine}}\)
= \(\frac{E3}{E2}\)
There is an explanation video available .