A siren having a ring of 200 hole makes 132 rev/min. A jet of air is directed on the set of holes. Calculate the frequency and wavelength in air of the note produced (take v = 350m/s)
-
0.795m
- 0.625m
- 0.335m
- 0.125m
The correct answer is: A
Explanation
n = 200, S = 132 rev/min, v = 350m/s\(^2\)
| f | = | ns | = | 200 | × | 132 | rev
min |
× | 1min
60s |
= | 440Hz |
| λ | = | v
f |
= | 350
440 |
= | 0.795m |
There is an explanation video available .