Three resistors with resistance 200Ω, 500Ω and 1kΩ are connected in series. A 6v battery is connected to either end of the combination. Calculate the potential difference between the ends of 200Ω resistance.
-
0.71V
- 0.7V
- 0.82V
- 0.8V
The correct answer is: A
Explanation
Req = 200 + 500 + 1000 = 1700Ω
| P.d | (across | 200Ω) | = | 200
1700 |
× | 6 | = | 0.71V |
There is an explanation video available .