An a.c of 1A at a frequency of 800 cycles per second flows through a coil, the inductance of which is 2.5mH and the resistance of which is 5Ω. What is the power absorbed in the Coil?
-
5W
- 6W
- 7W
- 8W
The correct answer is: A
Explanation
I = 1A, F = 800 cycles/s = 800Hz
R = 5Ω, L = 2.5mH
P = I\(^2\)R = I\(^2\) × 5 = 5W
There is an explanation video available .