The length of the seconds hand of laboratory clock is 0.1m. Calculate the speed at the top of the seconds hand
-
1.05 × 10\(^{-2}\)ms\(^{-1}\)
- 1.85 × 10\(^{-4}\)ms\(^{-1}\)
- 9.50 × 10\(^{-1}\)ms\(^{-1}\)
- 5.25 × 10\(^{-3}\)ms\(^{-1}\)
The correct answer is: A
Explanation
Length of the seconds hand = r = 0.1m but the seconds hand rotates through 360° or 2π rad in 60s.
| Thus, | ω | = | θ | = | 2π
60 |
Velocity of the tip of the hand, V = ωr
| V | = | 2π
60 |
× | 0.1 | = | 2π
600 |
= | π
300 |
= | 3.142
300 |
V = 0.01047 = 1.05 × 10\(^{-2}\)ms\(^{-1}\)
There is an explanation video available .