The diagram shows a uniform meter rule AB which balances horizontally at the 90cm mark when a mass of 0.2kg is suspended from B. Calculate the mass of the meter rule.
-
0.05kg
- 0.20kg
- 0.80kg
- 1.00kg
The correct answer is: A
Explanation
M\(_r\)(90 - 50) = 0.2(100 - 90)
40M\(_r\) = 0.2 × 10
| M\(_r\) | = | 2
40 |
= | 0.05kg |
There is an explanation video available .