A source of sound produces waves in air of wavelength 1.65m. If the speed of sound in air is 330ms\(^{-1}\), the period of vibration in air is?
- 200
-
0.005
- 0.5
- 0.02
The correct answer is: B
Explanation
V = \(\frac{\lambda}{T}\)
: v = 330ms\(^{-1}\)
\(\lambda\) = 1.65m
T = ?
330 = 1.65
T = \(\frac{1.65}{330}\) = 0.005s
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