Calculate the heat energy required to vaporize 50g of water initially at 80ºC if the specific heat capacity of water is 4.23jg\(^{-1}\)k\(^{-1}\) (specific latent heat of vaporization of water is 2260jg\(^{-1}\)
- 530000J
- 23200J
- 17200J
-
130000J
The correct answer is: D
Explanation
H = mc\(\bigtriangleup\theta\) + mL
H = ?
m = 50g, c = 4.23J/gk,L = 2260, \(\bigtriangleup\theta\) = 80ºC
H = 50 [4.23 x 80 + 2260]
= 129920 \(\approx\) 130,000J
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