A 2H inductor has negligible resistance and is connected to a \(\frac{50}{\pi}\) Hz A.C supply. The reactance of the inductor is?
-
200\(\Omega\)
- 50\(\Omega\)
- \(\frac{100}{\pi}\)
- \(\frac{25}{\pi \Omega}\)
The correct answer is: A
Explanation
Given;
L = 2H
F = \(\frac{50}{\pi}\) H\(_{2}\)
X\(_{L}\) = ?
X\(_{L}\) = 2\(\pi\)fL = 2\(\pi\) x \(\frac{50}{\lambda}\) x 2
= 200\(\Omega\)
There is an explanation video available .