A car starts from rest and covers a distance of 40 m in 10 s. Calculate the magnitude of its acceleration
- 3.20 ms\(^{-2}\)
- 0.25 ms\(^{-2}\)
-
0.80 ms\(^{-2}\)
- 4.00 ms\(^{-2}\)
The correct answer is: C
Explanation
S = ut + \(\frac{1}{2}\)at\(^2\)
40 = 0 x 10 + \(\frac{1}{2}\)a x 10\(^2\)
50a = 40
a = \(\frac{40}{50}\)
= 0.8m/s\(^2\)
There is an explanation video available .