A reservoir is filled with liquid of density 2000 kgm\(^{-1}\). Calculate the depth at which the pressure in the liquid will be equal to 9100 Nm\(^{-2}\) (g = 10 ms\(^{-2}\))
- 0.262 m
- 0.664 m
- 0.819 m
-
0.455 m
The correct answer is: D
Explanation
pressure = p, depth/height = h, density = d, gravity = g
p = hdg
\(\frac{p}{dg} = h\)
\(\frac{9100}{10 * 2000} = h\)
0.455m
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