What quantity of heat is required to convert 20 g of ice at 0 ºC to water at the same temperature? (Specific latent heat of ice = 336 Jg\(^{-1}\))
- 7.06 x 10\(^{3}\)J
- 5.38 x 10\(^{3}\)J
-
6.72 x 10\(^{3}\)J
- 1.35 x 10\(^{3}\)J
The correct answer is: C
Explanation
quantity of heat = mass * Specific latent heat → 20 * 336
quantity of heat = 6720j or 6.72 x 10\(^{3}\)J
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