Calculate the absolute pressure at the bottom of a lake at a depth of 32.8 m. Assume the density of the water is 1 x 10^3 kgm-3 and the air above is at a pressure of 101.3 kPa.
[Take g = 9.8 ms-2]
-
422.7
- 220.14
- 464.53
- 321.74
The correct answer is: A
Explanation
h=32ยท8m, p= \(1ร10^3kgm^-3\)
g=9ยท8 \(ms^-2\) , \(P_a\)=101ยท3KPa
\(P_T\)= ?
P=hpg
โ\(32ยท8ร1ร10^3 ร 9ยท8\)=321440 \(P_a\)
โ321ยท44KPa
โ \(P_T\) =321.44+101.3
;\(P_T\)=422ยท7KPa
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