A lorry accelerates uniformly in a straight line with acceleration of \(4ms^-2\) and covers a distance of 250 m in a time interval of 10 s. How far will it travel in the next 10 s?
-
650
- 900
- 800
- 250
The correct answer is: A
Explanation
We first find the lorry's initial velocity
a = \(4ms^-2\), s= 250m, t= 10, u=?
โ ut + \(\frac{1}{2}ร4ร(10^2)
โ250= 10u + 200
โ 250-200 = 10u
โ 50 = 10u
โU =\frac{50}{10}\) = \(5ms^-1\)
For the next 10s, we set t=20s
= s = (5 ร 20) + \(\frac{1}{2}ร4ร{20^2}\)
= s = 100 + 800
โ 900 m
;Distance covered:900-250 =650m
There is an explanation video available .