A parallel plate capacitor separated by an air gap is made of \(0.8m^2\) tin plates and 20 mm apart. It is connected to 120 V battery. What is the charge on each plate?
Take \(Ξ΅_o\) = \(8.85Γ10^-12 Fm^-1\)
- 3.54nC
-
42.5nC
- 35.4nC
- 4.25nC
The correct answer is: B
Explanation
A= \(0.8m^2\) d= 20mm =\(\frac{20}{1000}\) = 0.02m
v =120v; \(Ξ΅_oA\)= \(8.85 Γ 10^-12 fm^-1\)
C = \(\frac{Ξ΅_oA}{d}\)
C =\(\frac{8.85 Γ 10^-12Γ0.8}{0.02}\)
C= \(3.54 Γ 10^-10 F\)
Q= CV
β \(3.54 Γ 10^-10\) Γ 120 = \(4.25Γ10^-8c\)
Q=\(42.5 Γ 10^-9c\) = 42.5nC
There is an explanation video available .