A charge of \(4.6 × 10^{-5}\)C is placed in an electric field of intensity \(3.2 × 10^4\) \(Vm^{-1}\). What is the force acting on the electron?
-
1.5 N
- 3.7 N
- 4.2 N
- 2.5 N
The correct answer is: A
Explanation
q=\(4.6 × 10^{-5}\), C= \(3.2 × 10^4\) \(Vm^{-1}\) F= ?
F=qE
⇒ \(4.6 × 10^{-5}\)C × \(3.2 × 10^4\)
; F= 1.5 N
There is an explanation video available .