If the S.V.P of water vapour was 13.5mmHg at 33ºC and 7.3mmHg at 7ºC. Find the percentage relative of the air on a day when average air temperature was 33ºC and dew point was 7ºC.
- 55%
- 60%
-
54%
- 51%
The correct answer is: C
Explanation
Relative humidity = \(\frac{\text{S.V.P at dew point}}{\text{S.V.P at air temperature}}\)
S.V.P at dew point = 7.3mmHg
S.V.P at air temperature = 13.5mmHg
R.H = \(\frac{7.3}{13.5}\) x 100 \(\approxeq\) 54%
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