The moon’s acceleration due to gravity is \(\frac{1}{6}\) of the earth’s value. The weight of a bowling ball on the moon would be
- 6 times its weight on the earth
-
\(\frac{1}{6}\) of its weight on the earth
- 36 times its weight on the earth
- equal to its weight on the earth
The correct answer is: B
Explanation
W\(_{moon}\) = mass x g = mass x \(\frac{10}{6}\) = \(\frac{10m}{6}\)N
W\(_{earth}\) = mass x g = mass x 10 = 10m
mass = constant
g on earth = 10m/s\(^2\) and g on moon = \(\frac{1}{6}\) x that on earth
Therefore, The weight of a bowling ball on the moon would be \(\frac{1}{6}\), the weight on earth.
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