A mass of gas at 40mmHg is heated from 298k to 348k at constant volume. Cal the pressure exerted by the gas.
- 50.21mmHg
-
46.71mmHg
- 42.35mmHg
- 35.12mmHg
The correct answer is: B
Explanation
From pressure law
\(\frac{P_1}{T_1} = \frac{P_2}{T_2}\)
P\(_2\) = \(\frac{P_1 \times T_2}{T_1}\)
P\(_1\) = 40mmHg, P\(_2\) = ?
T\(_1\) = 298k, T\(_2\) = 348k
\(\frac{40}{298} = \frac{P_2}{348}\)
P\(_2\) = \(\frac{40\times348}{298}\) = 46.71mmHg
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