The distance between two successive crests of a water wave is 0.25m. If a particle on the surface of the water makes four complete vertical oscillations in one second. Calculate the speed of the wave.
- 4ms\(^{-1}\)
- 3ms\(^{-1}\)
- 2ms\(^{-1}\)
-
1ms\(^{-1}\)
The correct answer is: D
Explanation
distance between two successive crests of a water wave = \(\lambda\) = 0.25m
Frequency (f) is defined as the number of cycles or oscillations that occur in one second = four complete vertical oscillations in one second = 4Hz
Speed of wave (v) = f x \(\lambda\) = 0.25 x 4 = 1m/s
There is an explanation video available .