A load of 300N is to be lifted by a machine with a velocity ratio…

Explanation

Efficiency = \(\frac{\text{ M.A}}{\text{V.R}}\) x 100

M.A = \(\frac{\text{LOAD}}{\text{EFFORT}}\)

V.R = 2, Eff. = 60% = 0.6, Load = 300N

0.6 = \(\frac{\text{M.A}}{2}\)

M.A = 1.2

1.2 = \(\frac{300}{\text{E}}\)

Effort = \(\frac{300}{1.2}\) = 250N

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